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5a^2+35a+30=0
a = 5; b = 35; c = +30;
Δ = b2-4ac
Δ = 352-4·5·30
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-25}{2*5}=\frac{-60}{10} =-6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+25}{2*5}=\frac{-10}{10} =-1 $
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